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Câu 1 ( o,g /cm3 )
o = m (g/cm3 ),(kg/dm3 ),(T/m3 ) o
->m1=m+mparafin
.ngâm ng ->FAS = ΔP(m1−m2)g (1) FAS = (Vo +Vparafin).n.g (2)
Vparafin).n..g(m1−m2).g
= m (g /cm3 ) m1−m2 − m1−m
n parafin
m1−m2 m1−m2
o+Vparafin o parafin n n
n =1g /cm3 o = n m−m2
->m1 -mô`ng
- ∈ o
+ ∈
o = m1−mô`ng ô`ng
3 -BT: = 1,8 -2,5g/cm
- = 0,5 - 1,8
3 g/cm
- <0,5
3 g/cm
- =2,5 - 5
3 g/cm
- - 25 MPa - - 50 MPa
1
-BT cao : 60 - 100 MPa -
-
--
-
-
-
H2O
3CaO.SiO2 , 2Ca.SiO2,3Ca.Al2O ,4Ca.Al2O .Fe2O
i:
- - -
--
-
-2cm.
2
-88%), h(8-11%),,O(0-1,5%),,S(0-6%),,N(0-
to
max
- F (N/mm3 = MPa) pmax
-
Ri tb n
Rtb
-
-
-
--
-
-
-3cm)
3
- 10 cm
-4 cm
- 20 cm
-
--
->ch
-0,6% -2%
->Fe
6-10. 12-42.
-
Δl =l1 −l0
4
= Δl.100% 0
= F0 − Fk .100% 0
Edh = đh
đh
0<1 <2
- :
1 = 1 1 P=P22 = P 2
Eđh = tg = 2 −1 2 1
-
- = E.
-
-
--
-
Bê tôn
3 -BT: = 1,8 -2,5g/cm
- = 0,5 - 1,8
3 g/cm
- <0,5
3 g/cm
- =2,5 - 5
3 g/cm
- - 25 MPa - - 50 MPa
-BT cao : 60 - 100 MPa -
32 -
-
5
...
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